On 10/18/01 18:03, "Kerry Thompson" <[EMAIL PROTECTED]> wrote:

> 
>> Could anyone provide some advice on how to to calculate decibels from a
>> sample value for a peak meter...or perhaps just point me in the right
>> direction?
> 
> It looks like Dennis Flood uses the same formulas I use. His:
> ( log( inputValue / maxInputValue ) )*10
> 
> I usually write it
> 
> 20 log       (P actual / P ref)
>           10
> 
> where P is the sound pressure. For multiple, uncorrelated sources, P actual
> becomes the square root of the sum of the squares of P for the different
> sources. In other words, for practical purposes,
> 
> 20 log       (sqrt(P   ^2 + P     ^2 + ... P     ^2)
>           10             1            2                 n
> 
> which is the same as
> 
> 10 log       (P actual / P ref)
>           10
> 
> I hope the formatting comes out ok--I had to put subscripts on the line
> below since html e-mail is frowned upon (there is an email still smoldering
> in my system, somewhere, from an html post I did 3 years ago).
> 
> 
> Cordially,
> 
> Kerry Thompson
> 
> 
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> 
Ah Kerry...

Thank-you!..much appreciated.

This is perfect. Formatting (or lack thereof) is a little funny but I think
I have just enough meager knowledge to put it all together. <grin>

Again thanks!

Best Regards,

Joe


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