kendall anderson wrote:
> ...
> I realize this could be done with:
> if (total > 0) then
> dpercent = score/total
> else
> dpercent = 0
> end if
> return dpercent
>
> I'm just looking for a more compact, more 'elegant' solution. I also
> understand this is really a minor point. :)
Elegance is in the eye of they next poor sod to try to figure out the code.
Compact but only so readable:
dpercent = [0,score/total][1+(total>0)]
or
dpercent = [score/total,0][2-(total>0)]
for that matter, something like this might get you where you want to go:
dpercent = int(score/max(.0001,total))
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