Hello All,
There are still problems with Linrad under Windows.
The most frustrating one is that I can not find out
how to close the output device and then open it
again.
Currently the code (wsetad.c) is like this:
mmrs=waveOutReset(hwav_rxdaout);
if(mmrs != MMSYSERR_NOERROR)lirerr(25344);
for(i=0; i<NO_OF_RX_WAVEOUT; i++)
{
whdr=rxdaout_newbuf[i];
while( (whdr[0].dwFlags&WHDR_INQUEUE) != 0)lir_sleep(3000);
mmrs=waveOutUnprepareHeader(hwav_rxdaout, whdr, sizeof(WAVEHDR));
if(mmrs != MMSYSERR_NOERROR)lirerr(25144);
}
mmrs=waveOutClose(hwav_rxdaout);
if(mmrs != MMSYSERR_NOERROR)lirerr(25344);
>From the Microsoft site I can not get any information
that suggests something to be wrong here. The open routine
that works fine on the initial open uses this code:
mmrs=waveOutPause(hwav_rxdaout);
if(mmrs != MMSYSERR_NOERROR) lirerr(1238);
waveout_buf=malloc(NO_OF_RX_WAVEOUT*daout_block+fmt.nBlockAlign);
if(waveout_buf==NULL)goto wave_close;
wave_outhdr=malloc(NO_OF_RX_WAVEOUT*sizeof(WAVEHDR));
if(wave_outhdr==NULL)goto free_waveout;
da_wrbuf=malloc(daout_block);
if(da_wrbuf==NULL)goto free_outhdr;
for(i=0; i<NO_OF_RX_WAVEOUT; i++)
{
k=(int)(waveout_buf+i*daout_block+fmt.nBlockAlign);
k&=(-1-fmt.nBlockAlign);
wave_outhdr[i].lpData=(char*)(k);
wave_outhdr[i].dwBufferLength=daout_block;
wave_outhdr[i].dwBytesRecorded=0;
wave_outhdr[i].dwUser=1;
wave_outhdr[i].dwFlags=0;
wave_outhdr[i].dwLoops=0;
wave_outhdr[i].lpNext=NULL;
wave_outhdr[i].reserved=0;
mmrs=waveOutPrepareHeader(hwav_rxdaout, &wave_outhdr[i], sizeof(WAVEHDR));
rxdaout_newbuf[i]=&wave_outhdr[i];
if(mmrs != MMSYSERR_NOERROR)goto errfree;
}
Each system call generates MMSYSERR_NOERROR so there is no error exit.
Nevertheless the
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