On Tue, Sep 25, 2012 at 10:01 AM, <[email protected]> wrote:

> umask only works for the user/group/other bits of the file, not for the
> special bits so you should never see something like a 1077 returned as a
> umask


True - the value for the special bits only has meaning for chmod to
actually set those bits for a directory or file -- not umask.   So it will
always be 0 in the context of umask.

Scott Rohling


>

----------------------------------------------------------------------
For LINUX-390 subscribe / signoff / archive access instructions,
send email to [email protected] with the message: INFO LINUX-390 or visit
http://www.marist.edu/htbin/wlvindex?LINUX-390
----------------------------------------------------------------------
For more information on Linux on System z, visit
http://wiki.linuxvm.org/

Reply via email to