On Tuesday 07 February 2006 19:20, Luck, Tony wrote:
> > The fix is to include a __delay(1) call in the loop, to correctly 
> > approximate
> > the intended delay timeout of 1 second.  The code assumes that every
> > architecture implements __delay(1) to last around 1/(loops_per_jiffy*HZ)
> > seconds.
> 
> But we calculate loops_per_jiffy based on somewhat larger vales passed
> to __delay() ... where the function call overhead is amortized away.
>
> I'd expect that __delay(1) would last quite a bit longer than
> 1/(loops_per_jiffy * HZ) ... so we'll wait a lot more than a
> second.

For this case that would be ok, as long as it isn't a hour or so,
but let's say < 1 minute.

-Andi

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