David Howells writes:

> +     CPU 1           CPU 2           COMMENT
> +     =============== =============== =======================================
> +                                     a == 0, b == 1 and p == &a, q == &a
> +     b = 2;
> +     smp_wmb();                      Make sure b is changed before p
> +     p = &b;         q = p;
> +                     d = *q;
> +
> +then old data values may be used in the address calculation for the second
> +value, potentially resulting in q == &b and d == 0 being seen, which is never
> +correct.  What is required is a data dependency memory barrier:

No, that's not the problem.  The problem is that you can get q == &b
and d == 1, believe it or not.  That is, you can see the new value of
the pointer but the old value of the thing pointed to.

Paul.
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