Hi RMK,
I have a requirement where I need around ~100 bytes of memory to save
contents of
registers to a non-cached area before going into low power mode.
I did do some analysis on a 1GB RAM device of allocating 8 bytes using
the API and the below was the result
was showing allocating only 8 bytes.
API used : - arm_memblock_steal(SZ_8, SZ_64K);--> physical address
returned is 0x3b1f0000
/data/debug/memblock # cat memory
0: 0x00200000..0x3b1effff
1: 0x3b1f0008..0x3b1fffff [0x3b1f0000-0x3b1f0007] only 8 bytes removed.
/data/debug/memblock # cat reserved
0: 0x00204000..0x00c710fb
1: 0x01400000..0x01429b44
2: 0x0ffe0000..0x0ffeffff
3: 0x2d9f3000..0x2d9fffff
4: 0x3b1f0008..0x3b1fffff
But before I can go ahead and use this if you could confirm that it will
allocate only the size requested or it
will carve out minimum 1MB?
Also is this API advisable for devices with low system RAM?
--
Thanks& Regards,
Taniya Das.
Consultant for Qualcomm Innovation Center, Inc.
Qualcomm Innovation Center, Inc. is a member of Code Aurora Forum
--
To unsubscribe from this list: send the line "unsubscribe linux-arm-msm" in
the body of a message to [email protected]
More majordomo info at http://vger.kernel.org/majordomo-info.html
