Russell King - ARM Linux Admin wrote: > > I am having trouble understanding what this section is trying to > > accomplish. I have TEXTADDR defined as D8000. The first two stores > > appear to be writing the same value to the same address. I assume '<<' > > means shift left and '>>' means shift right. > > > > I assume TEXTADDR is the base address of executable code? Why the > > 0x8000 test at the start of this code? > > > > What advice is available for mapping physical to virtual addresses? > > Hmm, have you had any experience with ARM assembly programming? I'd like > to know this so that I can pitch my reply appropriately. I am a newbie that is rapidly coming up to speed. I have all the documentation for ARM. Our target is not one of the currently supported targets but it is in the ARM7 family. Which architecture should I study? I am still looking for some information on the code that I included in my last message. Thanks, Scott unsubscribe: body of `unsubscribe linux-arm' to [EMAIL PROTECTED] ++ Please use [EMAIL PROTECTED] for ++ ++ kernel-related discussions. ++
