On Fri, Feb 24, 2023 at 12:14:19PM +0100, Stefano D'Angelo wrote: > > Given any three points (x1, y1), (x2, (y1+y3)/2), (x3, y3) where > > y1>y2>y3 or y1<y2<y3 you can find an exponential function passing > > through them as explained here: > > https://www.orastron.com/blog/potentiometers-parameter-mapping-part-1 > > (+ "output scaling"). > > Sorry, typo: I meant points (x1,y1), ((x1+x3)/2,y2), (x3,y3).
That function may include some exponential term, but If F (x) = A exp (B * x) # A pure exponential then F ((x1 + x2) / 2) = sqrt (F (x1) * F (x2)) So the mid point is fixed, you can't choose it. Ciao, -- FA _______________________________________________ Linux-audio-dev mailing list -- linux-audio-dev@lists.linuxaudio.org To unsubscribe send an email to linux-audio-dev-le...@lists.linuxaudio.org
