but lets say O(log N/2) where N is the number of elements in the row. So in the situation I describe you are looking at having to do minimum of 29 reads, one for each row,
Hmm. Levels are powers of two and are either full or empty. So the total item count tells you which levels are full or empty. (gdb) print/t 1000000000 $3 = 111011100110101100101000000000 So no, definitely not reading 29 levels. After realizing this, I have to be honest: I'm not finding your hand-wavey dismissal of the technology convincing at all. :) There's a *ton* of detail that they don't describe about how to actually translate the logical notion of power-of-two node sizes into coherent block IO that scales. I don't doubt that it's possible. I very much doubt that the required complexity and cpu cost in the kernel would be worth it for generic file system users, though. Hooo boy, do I doubt it. - z -- To unsubscribe from this list: send the line "unsubscribe linux-btrfs" in the body of a message to majord...@vger.kernel.org More majordomo info at http://vger.kernel.org/majordomo-info.html
