On      thu, 24 Oct 2013 19:32:15 +0800, Wang Shilong wrote:
> On 10/24/2013 06:08 PM, Chris Mason wrote:
>> Quoting Stefan Behrens (2013-10-23 13:21:34)
>>> On Tue, 22 Oct 2013 18:55:59 +0200, Bob Marley wrote:
>>>> On 22/10/2013 10:37, Stefan Behrens wrote:
>>>>> I don't believe that this issue can ever happen. I don't believe that
>>>>> somewhere on the path to the flash memory, to the magnetic disc or to
>>>>> the drive's cache memory, someone interrupts a 4KB write in the middle
>>>>> of operation to read from this 4KB area. This is not an issue IMHO.
>>>> I think I have read that unfortunately it can happen.
>>>> SAS and SATA specs for disks do not mandate that if a write is in-flight
>>>> but still not completed, reads from the same sector should return the
>>>> value it is being written; they can return the old value.
>>>> I also think that Linux does not check either.
>>> If the _old_ 4KB block is returned, that's fine and won't cause a
>>> checksum error.
>>>
>>> The patch in question addresses the case that Btrfs submits a write
>>> request for a 4KB block, and a concurrent read request for that 4KB
>>> block reads partially the old block and partially the new block,
>>> resulting in a checksum error reported in the scrub statistic counters.
>> Concurrent reads and writes to the device are completely undefined, and
>> Any combination of old, new, random memory corruption wouldn't
>> surprise me...I'd rather avoid them ;)
>>
>> Doing the transaction join during the super read is probably the least
>> complex choice.
> Yeah, by joining transaction we can solve this problem, but it is a little 
> confused,
> because we don't involve writting in scrubing supers.
> 
> And the only race condition happens in commiting transaction, Miao also 
> pointed out that
> maybe the best way is to move btrfs_scrub_continue after write_ctree_super().

Sorry, My miss.

btrfs_scrub_continue() is behind write_ctree_super() all the while, so the 
above problem
doesn't exist.

Thanks
Miao

> 
> Thanks,
> Wang
>> -chris
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