Hello all,
I want to take a floating point number and determine it's binary
represention. This seems easy enough as the answer is right there in
memory. I can do this with a debugger, but other than dicking around with
memcopies, I can't see an easy way to print out the memory contents of
arbitrary data.
So here is what I have thus far (I know, it's a disgusting conglomeration of
C and C++ but that's how I code).
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#include <iostream.h>
#include <string.h>
#include <iomanip.h>
main()
{
float f = 903996940.376776;
double d = 903996940.376776;
unsigned int i_f,i_d1,i_d2;
memcpy ( (void*)&i_f, (void*)&f,4);
memcpy ( (void*)&i_d1, (void*)&d,4);
memcpy ( (void*)&i_d2, (void*)((&d)+4),4);
cout <<hex<<&d<<"\t"<<(&d)+4<<"\t"<<i_f<<"\t"<<i_d1<<"\t"<<i_d2<<
endl;
}
Here is the output
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1 1 4e578798 6303a32 0
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What seems wrong is that &d and (&d)+4 have the same value (and it's
apparently 1 ??). Because doubles are 64-bit, I tried to partition the
memcopy into two separate ints. However, I've done something silly whilst
trying to increment 4 bytes in memory. It seems like simple pointer
arithmetic to moi, so I'll ask some good coders -- what gives?
Thanks,
Andy
