Chetan Sakhardande wrote:
> WHat is an asynchronous socket? Is it a UDP socket?
An asynchronous socket is one which has had the O_ASYNC flag set on
it, with e.g.
flags = fcntl(fd, F_GETFL, 0);
flags |= O_ASYNC;
fcntl(fd, F_SETFL, flags);
fcntl(fd, F_SETOWN, getpid());
This will cause the process to receive SIGIO whenever there is data
available.
> Can you use a TCP connection in Asynchronous mode ?
Yes.
> the stdio library is line buffered. Can we change this setting ?
stdio streams default to being line buffered if the stream refers to a
tty device (something for which isatty() returns nonzero), and fully
buffered otherwise.
You can change the buffering mode of a stream using any of setbuf(),
setbuffer(), setlinebuf(), or setvbuf().
> in the foll. code:
>
> inline void foo(int j)
> {
> int g;
> }
>
> int main(void)
> {
> int f;
>
> foo(f);
>
> exit(0);
> }
>
> According to inline functions def., the foo(f) call in main is expanded to
> the funciton defn. i.e. the compiler does not generate a call.
>
> However when compiled g++ -g foo.c , and using gdb we get for disass..
> main :
[snip]
> WHy is the call to foo there? why don't i see code of foo instead.
According to the Info file, gcc never inlines functions if it isn't
optimising. Try adding `-O' to your compile switches.
> I tried doing the same without the inline specification and got :
[snip]
> That extra <main+34> in the prev case is funny. What does it mean?
Nothing. gdb is just disassembling too much data. The function ends at
the `ret' statement.
> when using a const instance, we must use a const method defined like :
> ... foo() const;
>
> What is the meaning of a const method ?
It means that it doesn't modify the object upon which it is called
(i.e. the one to which `this' refers).
> Can this be static also?
It isn't applicable to static (class) methods.
> Is there a man page available for C++ librarires like iostream
No, but there are Info files for libg++ and the iostream library.
--
Glynn Clements <[EMAIL PROTECTED]>
