Re: poniter problem

[Glynn Clements]

Amol Mohite wrote:

> I meant something like :
> 
> *i = ((int *)c++);
> 
> I guess this will work like doing (int *)++c.

No. It will be equivalent to:

        *i = (int *)c;
        c++;

The increment is done after the expression is evaluated.

> Sorry i meesd the brackets.

The brackets don't have any effect upon the result.

-- 
Glynn Clements <[EMAIL PROTECTED]>