On Thu, 09 Dec 1999, John Seifarth wrote:
> I don't know perl, but as I was perusing the diald.monthly source, I
> noticed the following on line 23:
>
> $year = 1900 + $time[5];
>
> Now doesn't this look suspiciously like a Y2K problem?
>
> What should be done so that it works 20 days from now?
Actually no. Thats the proper, Y2K Compliant way to do that.
The broken way would be '$year = 19 . $time[5]'; which would start
displaying '19100' in the Y2K. $time[5] (part of the output from
localtime()) holds the number of years from 1900, so its Y2K safe if used in
that way.
>
> John
> __________________________________________________________________
> John Seifarth http://www.waw.be/waw/
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>
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