The regular expression currently expects a single word for the
type, but it may be something like  "struct foo".

Add support for it.

Signed-off-by: Mauro Carvalho Chehab <[email protected]>
Acked-by: Randy Dunlap <[email protected]>
Tested-by: Randy Dunlap <[email protected]>
---
 tools/lib/python/kdoc/kdoc_parser.py | 4 ++--
 1 file changed, 2 insertions(+), 2 deletions(-)

diff --git a/tools/lib/python/kdoc/kdoc_parser.py 
b/tools/lib/python/kdoc/kdoc_parser.py
index 0b6cba442d72..21cc4e19a1e8 100644
--- a/tools/lib/python/kdoc/kdoc_parser.py
+++ b/tools/lib/python/kdoc/kdoc_parser.py
@@ -1026,7 +1026,7 @@ class KernelDoc:
 
         default_val = None
 
-        r= KernRe(OPTIONAL_VAR_ATTR + 
r"[\w_]*\s+(?:\*+)?([\w_]+)\s*[\d\]\[]*\s*(=.*)?")
+        r= KernRe(OPTIONAL_VAR_ATTR + 
r"\s*[\w_\s]*\s+(?:\*+)?([\w_]+)\s*[\d\]\[]*\s*(=.*)?")
         if r.match(proto):
             if not declaration_name:
                 declaration_name = r.group(1)
@@ -1037,7 +1037,7 @@ class KernelDoc:
                                   r.groups(), proto)
 
         else:
-            r= KernRe(OPTIONAL_VAR_ATTR + 
r"(?:[\w_]*)?\s+(?:\*+)?(?:[\w_]+)\s*[\d\]\[]*\s*(=.*)?")
+            r= KernRe(OPTIONAL_VAR_ATTR + 
r"(?:[\w_\s]*)?\s+(?:\*+)?(?:[\w_]+)\s*[\d\]\[]*\s*(=.*)?")
 
             if r.match(proto):
                 default_val = r.group(1)
-- 
2.52.0


Reply via email to