On Thu, 17 Mar 2005 23:17:29 -0800, 
David Mosberger <[EMAIL PROTECTED]> wrote:
>>>>>> On Fri, 18 Mar 2005 18:04:37 +1100, Keith Owens <[EMAIL PROTECTED]> said:
>
>  Keith> memcpy_mck.S::__copy_user breaks in the prefetch code under these
>  Keith> conditions :-
>
>  Keith> * src is unaligned and
>  Keith> * dst is near the end of a page and
>  Keith> * the page after dst is unmapped.
>
>  Keith> The loop count in r21 is 1 value too high.  A length of 0x100 gives
>  Keith> ar.lc == r21 == 2.  .unaligned_src incorrectly copies r21 into ar.lc,
>  Keith> when it should copy cnt, so the lfetch lines are executed 3 times, not
>  Keith> 2.  That takes dst_pre_mem past the end of the page and into an
>  Keith> unallocated area, oops.
>
>That's a good thing to fix (it's definitely a performance bug).  However,
>lfetch.fault should be safe to use even on unmapped memory.  See this
>code in ia64_do_page_fault():
>
> /*
>  * This fault was due to a speculative load or lfetch.fault, set the "ed"
>  * bit in the psr to ensure forward progress.  (Target register will get a
>  * NaT for ld.s, lfetch will be canceled.)
>  */
>
>I don't see off-hand why this wouldn't work as intended.

It's got me puzzled as well.  On my test system, single stepping the
offending instruction _WILL_ cause a fault, but letting it run normally
does not cause an error.  A normal run (without single step) definitely
uses lfetch with an invalid address, however ia64_fault() is not
invoked, not even for isr.na.

I am trying to get some time on the big system to reproduce the problem
and see why lfetch is faulting there.  Is there any chance that a
concurrent interrupt (the failing system does a lot of I/O) can lose
the lfetch status?

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