Hello, I wrote:
HPT36x chip don't seem to have the channel enable bits, so prevent the IDE core
from checking them...

Signed-off-by: Sergei Shtylyov <[EMAIL PROTECTED]>

Index: linux-2.6/drivers/ide/pci/hpt366.c
===================================================================
--- linux-2.6.orig/drivers/ide/pci/hpt366.c
+++ linux-2.6/drivers/ide/pci/hpt366.c
@@ -1,5 +1,5 @@
 /*
- * linux/drivers/ide/pci/hpt366.c              Version 1.02    Apr 18, 2007
+ * linux/drivers/ide/pci/hpt366.c              Version 1.03    May 4, 2007
  *
  * Copyright (C) 1999-2003             Andre Hedrick <[EMAIL PROTECTED]>
  * Portions Copyright (C) 2001         Sun Microsystems, Inc.
@@ -1527,7 +1527,12 @@ static int __devinit init_setup_hpt366(s
        if (rev > 2)
                goto init_single;
+ /*
+        * HPT36x chips are single channel and
+        * do not seem to have the channel enable bit...
+        */

   Actually it does, but the bit is different. :-/

        d->channels = 1;
+       d->enablebits[0].reg = 0;

   Linas, Andries, Michal, cound you try this instead:

        d->enablebits[0].mask = d->enablebits[0].val = 0x10;

        if ((dev2 = pci_get_slot(dev->bus, dev->devfn + 1)) != NULL) {
                u8  pin1 = 0, pin2 = 0;

MBR, Sergei
-
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