thanks all for answering, now i get it ( i think )
btw: can i exchange stderr and stdout ? ( 2>1 1>2 ? )
what does the '&' stand for in the "2>&1" can i do 2>1 ? what is the
difference ?
Oleg Goldshmidt wrote:
>Alex Shnitman <[EMAIL PROTECTED]> writes:
>
>>On Thu, 2002-09-12 at 16:03, [EMAIL PROTECTED] wrote:
>>
>>>i want to redirect both strdout and stderror into a pipe
>>>
>>>in tcsh i do: process1 |& process2
>>>how do i do it in sh ? in bash ? ( is that the same )
>>>
>>process1 2>&1 | process2
>>
>
>Note that this is not exactly what the OP asked for. What 2>&1 does
>is duplicates stderr to stdout, and then redirects stdout *only* to
>the pipe. See man bash for details.
>
>I suspect that the proper answer is
>
>process1 | 2>&1 process2
>
>Subtle details can be shown using the trivial
>
>#include <stdio.h>
>
>int main(void)
>{
> fprintf(stdout,"stdout\n");
> fflush(0);
> fprintf(stderr,"stderr\n");
> fflush(0);
> return 0;
>}
>
>$ a.out 2>&1 | cat
>stdout
>stderr
>$ a.out | 2>&1 cat
>stderr
>stdout
>$ a.out 2>/dev/null 2>&1 | cat
>stdout
>stderr
>$ a.out 2>/dev/null | 2>&1 cat
>stdout
>
>On the other hand, maybe "process1 2>&1 | process2" is exactly what
>the OP wanted, it was not quite clear. I just thought one should be
>aware of the difference.
>
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