[EMAIL PROTECTED] writes:
> Hi all,
>
> In order to avoid using undefined variables one can use the syntax:
> echo ${badvarname:?} which will result in error message would the
> variable be bad (not "defined" or empty). This kind of reference is
> tedious therefore one could use ksh -u (in a script)
> #!/bin/ksh -u
>
> the result is a check upon all variable references, which brings in a new
> problem.
>
> while ($1)
Did you mean,
while test $1
?
> do
> some stuff with $1
> shift
> done
>
> is there a solution for such a case?
Yes, use ${badvarname:?} where appropriate...
Your question seems contradictory to me: on the one hand, you want to
exit the shell if *any* of the variables you use is unset. On the
other hand, in your example your logic *relies* on a variable being
not set.
--
Oleg Goldshmidt | [EMAIL PROTECTED] | http://www.goldshmidt.org
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