Hi all, I am trying to use sed to seach and replace text in text files.
the problem is I can't find how to use an expression starting with a back slash and replace it with a % here is what I want: sed 's/\barNumberCheck/%/' 445n.ly >445w.ly one line from the file: g'4. d'8 g'4. b'16 [ b'16 ] | \barNumberCheck #20 What I want to happen: g'4. d'8 g'4. b'16 [ b'16 ] | % #20 obviously my attempt doesn't work. I need I gather to quote the backslash somehow, how? Thanks, Aaron Also does the percent sign need quoting? Thanks, A sed novice, Aaron ================================================================= To unsubscribe, send mail to [EMAIL PROTECTED] with the word "unsubscribe" in the message body, e.g., run the command echo unsubscribe | mail [EMAIL PROTECTED]
