The regular expression currently expects a single word for the type, but it may be something like "struct foo".
Add support for it. Signed-off-by: Mauro Carvalho Chehab <[email protected]> Acked-by: Randy Dunlap <[email protected]> Tested-by: Randy Dunlap <[email protected]> Reviewed-by: Aleksandr Loktionov <[email protected]> --- tools/lib/python/kdoc/kdoc_parser.py | 4 ++-- 1 file changed, 2 insertions(+), 2 deletions(-) diff --git a/tools/lib/python/kdoc/kdoc_parser.py b/tools/lib/python/kdoc/kdoc_parser.py index 39ff27d421eb..22a820d33dc8 100644 --- a/tools/lib/python/kdoc/kdoc_parser.py +++ b/tools/lib/python/kdoc/kdoc_parser.py @@ -1018,14 +1018,14 @@ class KernelDoc: default_val = None - r= KernRe(OPTIONAL_VAR_ATTR + r"[\w_]*\s+(?:\*+)?([\w_]+)\s*[\d\]\[]*\s*(=.*)?") + r= KernRe(OPTIONAL_VAR_ATTR + r"\s*[\w_\s]*\s+(?:\*+)?([\w_]+)\s*[\d\]\[]*\s*(=.*)?") if r.match(proto): if not declaration_name: declaration_name = r.group(1) default_val = r.group(2) else: - r= KernRe(OPTIONAL_VAR_ATTR + r"(?:[\w_]*)?\s+(?:\*+)?(?:[\w_]+)\s*[\d\]\[]*\s*(=.*)?") + r= KernRe(OPTIONAL_VAR_ATTR + r"(?:[\w_\s]*)?\s+(?:\*+)?(?:[\w_]+)\s*[\d\]\[]*\s*(=.*)?") if r.match(proto): default_val = r.group(1) -- 2.52.0
