On Mon 29-02-16 18:58:17, Oleg Nesterov wrote: > On 02/29, Michal Hocko wrote: > > > > On Mon 29-02-16 18:38:45, Oleg Nesterov wrote: > > > > > In this case you do not need put_task_struct(). > > > > Why not? Both are after get_proc_task which takes a reference to the > > task... > > Yes, but we already have put_task_struct(task) in the "out_mm" path, so > "goto out_mm" should work just fine?
OK, got what you mean now. That's what I did and is on the way. I just thought you mean that put_task_struct is implicit for other reason. -- Michal Hocko SUSE Labs
