On Mon, Nov 21, 2016 at 01:23:44PM +0100, Oleg Nesterov wrote:
> On 11/18, Davidlohr Bueso wrote:
> >
> > +static bool __readers_active_check(struct percpu_rw_semaphore *sem)
> > +{
> > + return !(per_cpu_sum(*sem->read_count) !=0);
> > +}
>
> Hmm,
>
> return per_cpu_sum(*sem->read_count) == 0;
>
> looks more clear, but this is minor,
Very much so; that must be one of the most convoluted statements
possible :-).
>
> > int __percpu_init_rwsem(struct percpu_rw_semaphore *sem,
> > const char *name, struct lock_class_key *rwsem_key)
> > {
> > @@ -103,41 +141,11 @@ void __percpu_up_read(struct percpu_rw_semaphore *sem)
> > __this_cpu_dec(*sem->read_count);
> >
> > /* Prod writer to recheck readers_active */
> > - swake_up(&sem->writer);
> > + if (__readers_active_check(sem))
> > + swake_up(&sem->writer);
>
> Suppose we have 2 active readers which call __percpu_up_read() at the same
> time and the pending writer sleeps.
>
> What guarantees that one of these readers will observe per_cpu_sum() == 0 ?
> They both can read the old value of the remote per-cpu counter, no?
In particular, you're thinking of what provides the guarantee that the
woken CPU observes the same state the wakee saw? Isn't this one of the
Program-Order guarantees the scheduler _should_ provide?
