stm32_vrefbuf_enable() wrongly checks VRR bit: 0 stands for not ready,
1 for ready. It currently checks the opposite.
This makes enable routine to exit immediately without waiting for ready
flag.
Fixes: 0cdbf481e927 ("regulator: Add support for stm32-vrefbuf")
Signed-off-by: Fabrice Gasnier <fabrice.gasn...@st.com>
---
drivers/regulator/stm32-vrefbuf.c | 2 +-
1 file changed, 1 insertion(+), 1 deletion(-)
diff --git a/drivers/regulator/stm32-vrefbuf.c
b/drivers/regulator/stm32-vrefbuf.c
index 72c8b3e..e0a9c44 100644
--- a/drivers/regulator/stm32-vrefbuf.c
+++ b/drivers/regulator/stm32-vrefbuf.c
@@ -51,7 +51,7 @@ static int stm32_vrefbuf_enable(struct regulator_dev *rdev)
* arbitrary timeout.
*/
ret = readl_poll_timeout(priv->base + STM32_VREFBUF_CSR, val,
- !(val & STM32_VRR), 650, 10000);
+ val & STM32_VRR, 650, 10000);
if (ret) {
dev_err(&rdev->dev, "stm32 vrefbuf timed out!\n");
val = readl_relaxed(priv->base + STM32_VREFBUF_CSR);
--
1.9.1
