One of the more common cases of allocation size calculations is finding
the size of a structure that has a zero-sized array at the end, along
with memory for some number of elements for that array. For example:
struct foo {
int stuff;
void *entry[];
};
instance = devm_kzalloc(dev, sizeof(struct foo) + sizeof(void *) * count,
GFP_KERNEL);
Instead of leaving these open-coded and prone to type mistakes, we can
now use the new struct_size() helper:
instance = devm_kzalloc(dev, struct_size(instance, entry, count), GFP_KERNEL);
Signed-off-by: Gustavo A. R. Silva <[email protected]>
---
drivers/mtd/nand/raw/jz4780_nand.c | 2 +-
1 file changed, 1 insertion(+), 1 deletion(-)
diff --git a/drivers/mtd/nand/raw/jz4780_nand.c
b/drivers/mtd/nand/raw/jz4780_nand.c
index db4fa60..ac62395 100644
--- a/drivers/mtd/nand/raw/jz4780_nand.c
+++ b/drivers/mtd/nand/raw/jz4780_nand.c
@@ -352,7 +352,7 @@ static int jz4780_nand_probe(struct platform_device *pdev)
return -ENODEV;
}
- nfc = devm_kzalloc(dev, sizeof(*nfc) + (sizeof(nfc->cs[0]) *
num_banks), GFP_KERNEL);
+ nfc = devm_kzalloc(dev, struct_size(nfc, cs, num_banks), GFP_KERNEL);
if (!nfc)
return -ENOMEM;
--
2.7.4
