Hi Ilias,
On Mon, Sep 14, 2020 at 07:03:55PM +0300, Ilias Apalodimas wrote:
> Running the eBPF test_verifier leads to random errors looking like this:
>
> [ 6525.735488] Unexpected kernel BRK exception at EL1
> [ 6525.735502] Internal error: ptrace BRK handler: f2000100 [#1] SMP
Does this happen because we poison the BPF memory with BRK instructions?
Maybe we should look at using a special immediate so we can detect this,
rather than end up in the ptrace handler.
> diff --git a/arch/arm64/net/bpf_jit_comp.c b/arch/arm64/net/bpf_jit_comp.c
> index f8912e45be7a..0974effff58c 100644
> --- a/arch/arm64/net/bpf_jit_comp.c
> +++ b/arch/arm64/net/bpf_jit_comp.c
> @@ -143,9 +143,13 @@ static inline void emit_addr_mov_i64(const int reg,
> const u64 val,
> }
> }
>
> -static inline int bpf2a64_offset(int bpf_to, int bpf_from,
> +static inline int bpf2a64_offset(int bpf_insn, int off,
> const struct jit_ctx *ctx)
> {
> + /* arm64 offset is relative to the branch instruction */
> + int bpf_from = bpf_insn + 1;
> + /* BPF JMP offset is relative to the next instruction */
> + int bpf_to = bpf_insn + off + 1;
> int to = ctx->offset[bpf_to];
> /* -1 to account for the Branch instruction */
> int from = ctx->offset[bpf_from] - 1;
I think this is a bit confusing with all the variables. How about just
doing:
/* BPF JMP offset is relative to the next BPF instruction */
bpf_insn++;
/*
* Whereas arm64 branch instructions encode the offset from the
* branch itself, so we must subtract 1 from the instruction offset.
*/
return ctx->offset[bpf_insn + off] - ctx->offset[bpf_insn] - 1;
> @@ -642,7 +646,7 @@ static int build_insn(const struct bpf_insn *insn, struct
> jit_ctx *ctx,
>
> /* JUMP off */
> case BPF_JMP | BPF_JA:
> - jmp_offset = bpf2a64_offset(i + off, i, ctx);
> + jmp_offset = bpf2a64_offset(i, off, ctx);
> check_imm26(jmp_offset);
> emit(A64_B(jmp_offset), ctx);
> break;
> @@ -669,7 +673,7 @@ static int build_insn(const struct bpf_insn *insn, struct
> jit_ctx *ctx,
> case BPF_JMP32 | BPF_JSLE | BPF_X:
> emit(A64_CMP(is64, dst, src), ctx);
> emit_cond_jmp:
> - jmp_offset = bpf2a64_offset(i + off, i, ctx);
> + jmp_offset = bpf2a64_offset(i, off, ctx);
> check_imm19(jmp_offset);
> switch (BPF_OP(code)) {
> case BPF_JEQ:
> @@ -912,18 +916,26 @@ static int build_body(struct jit_ctx *ctx, bool
> extra_pass)
> const struct bpf_insn *insn = &prog->insnsi[i];
> int ret;
>
> + /*
> + * offset[0] offset of the end of prologue, start of the
> + * first insn.
> + * offset[x] - offset of the end of x insn.
So does offset[1] point at the last arm64 instruction for the first BPF
instruction, or does it point to the first arm64 instruction for the second
BPF instruction?
> + */
> + if (ctx->image == NULL)
> + ctx->offset[i] = ctx->idx;
> +
> ret = build_insn(insn, ctx, extra_pass);
> if (ret > 0) {
> i++;
> if (ctx->image == NULL)
> - ctx->offset[i] = ctx->idx;
> + ctx->offset[i] = ctx->offset[i - 1];
Does it matter that we set the offset for both halves of a 16-byte BPF
instruction? I think that's a change in behaviour here.
> continue;
> }
> - if (ctx->image == NULL)
> - ctx->offset[i] = ctx->idx;
> if (ret)
> return ret;
> }
> + if (ctx->image == NULL)
> + ctx->offset[i] = ctx->idx;
I think it would be cleared to set ctx->offset[0] before the for loop (with
a comment about what it is) and then change the for loop to iterate from 1
all the way to prog->len.
Will
