On Tue, Oct 28, 2025 at 01:26:05PM -0700, Andrew Morton wrote:
> On Tue, 28 Oct 2025 22:28:10 +0530 Ankit Khushwaha
> <[email protected]> wrote:
>
> > > > @@ -236,7 +237,8 @@ TEST_F(user, perf_empty_events) {
> > > > ASSERT_EQ(1 << reg.enable_bit, self->check);
> > > >
> > > > /* Ensure write shows up at correct offset */
> > > > - ASSERT_NE(-1, write(self->data_fd, ®.write_index,
> > > > + memcpy(&write_index, ®.write_index, sizeof(reg.write_index));
> > > > + ASSERT_NE(-1, write(self->data_fd, &write_index,
> > > > sizeof(reg.write_index)));
> > >
> > > Simply casting &write_index to void* would fix this?
> >
> > yes, this hides the type mismatch from the compiler. But i think
> > casting to void * will not fix the alignment mismatch for packed struct.
> > It works on x86, but might break on other platform.
>
> It's the second argument to write(2)! write(2) expects a const char *,
> but void* will work.
Hi Andrew,
Indeed
`ASSERT_NE(-1, write(self->data_fd, (void *)®.write_index,
sizeof(reg.write_index)));`
would work. However since `reg` is packed struct, directly taking the
address of its member `®.write_index` may lead to unaligned access
on some architectures. as indicated by the compiler warning
perf_test.c:239:38: warning: taking address of packed member
'write_index' of class or structure 'user_reg' may result in
an unaligned pointer value [-Waddress-of-packed-member]
239 | ASSERT_NE(-1, write(self->data_fd, ®.write_index,
| ^~~~~~~~~~~~~~~
Using `memcpy` avoids this by performing a byte-wise copy, which is safe
to use for packed structures.
Thanks
-- Ankit