Alan Cox <[EMAIL PROTECTED]> writes:

> Suppose vesafb did something like this, dropping the printk lock
> 
>       if(test_and_set_bit(0, &vesafb_lock))
>       {
>               if(in_interrupt())
>               {
>                       // remember which bit of the dmesg ring to queue
>                       queued_writes=1;
>                       return;


Just what happens when you run out of dmesg ring in an interrupt ?


-Andi
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