From: Fabio Estevam <fabio.este...@freescale.com>
IPUv3 has a total of 3 flows (one synchronous flow and 2 asynchronous flows).
Let's add a definition for such number in order to let the code easier to
understand.
Signed-off-by: Fabio Estevam <fabio.este...@freescale.com>
---
drivers/staging/imx-drm/ipu-v3/ipu-dp.c | 6 ++++--
1 file changed, 4 insertions(+), 2 deletions(-)
diff --git a/drivers/staging/imx-drm/ipu-v3/ipu-dp.c
b/drivers/staging/imx-drm/ipu-v3/ipu-dp.c
index 6e0e9f1..3bdff6af 100644
--- a/drivers/staging/imx-drm/ipu-v3/ipu-dp.c
+++ b/drivers/staging/imx-drm/ipu-v3/ipu-dp.c
@@ -46,6 +46,8 @@
#define DP_COM_CONF_CSC_DEF_BG (2 << 8)
#define DP_COM_CONF_CSC_DEF_BOTH (1 << 8)
+#define IPUV3_NUM_FLOWS 3
+
struct ipu_dp_priv;
struct ipu_dp {
@@ -67,7 +69,7 @@ struct ipu_dp_priv {
struct ipu_soc *ipu;
struct device *dev;
void __iomem *base;
- struct ipu_flow flow[3];
+ struct ipu_flow flow[IPUV3_NUM_FLOWS];
struct mutex mutex;
int use_count;
};
@@ -322,7 +324,7 @@ int ipu_dp_init(struct ipu_soc *ipu, struct device *dev,
unsigned long base)
mutex_init(&priv->mutex);
- for (i = 0; i < 3; i++) {
+ for (i = 0; i < IPUV3_NUM_FLOWS; i++) {
priv->flow[i].foreground.foreground = 1;
priv->flow[i].base = priv->base + ipu_dp_flow_base[i];
priv->flow[i].priv = priv;
--
1.8.1.2
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