Cat snapshot give me:
" tracer: nop
* Snapshot is freed *
Snapshot commands:
echo 0 > snapshot : Clears and frees snapshot buffer
echo 1 > snapshot : Allocates snapshot buffer, if not already allocated.
Takes a snapshot of the main buffer.
echo 2 > snapshot : Clears snapshot buffer (but does not allocate)
(Doesn't have to be '2' works with any number that
is not a '0' or '1')"
But after read the code, I found the right information about "echo 2 > snapshot"
should looks like below:
" echo 2 > snapshot : Clears snapshot buffer (but does not free)
(Doesn't have to be '2' works with any number that
is not a '0' or '1')"
Signed-off-by: Wang YanQing <[email protected]>
---
kernel/trace/trace.c | 2 +-
1 file changed, 1 insertion(+), 1 deletion(-)
diff --git a/kernel/trace/trace.c b/kernel/trace/trace.c
index 7974ba2..d0da660 100644
--- a/kernel/trace/trace.c
+++ b/kernel/trace/trace.c
@@ -2760,7 +2760,7 @@ static void show_snapshot_main_help(struct seq_file *m)
seq_printf(m, "# echo 0 > snapshot : Clears and frees snapshot
buffer\n");
seq_printf(m, "# echo 1 > snapshot : Allocates snapshot buffer, if not
already allocated.\n");
seq_printf(m, "# Takes a snapshot of the main
buffer.\n");
- seq_printf(m, "# echo 2 > snapshot : Clears snapshot buffer (but does
not allocate)\n");
+ seq_printf(m, "# echo 2 > snapshot : Clears snapshot buffer (but does
not free)\n");
seq_printf(m, "# (Doesn't have to be '2' works
with any number that\n");
seq_printf(m, "# is not a '0' or '1')\n");
}
--
1.7.12.4.dirty
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