On Tue, Sep 23, 2014 at 09:03:48PM +0200, Oleg Nesterov wrote:
> On 09/22, Steven Rostedt wrote:
> >
> > On Mon, 22 Sep 2014 21:11:30 +0200
> > Oleg Nesterov <[email protected]> wrote:
> >
> > > > > @@ -1261,30 +1261,25 @@ struct sighand_struct 
> > > > > *__lock_task_sighand(struct task_struct *tsk,
> > > > >                                          unsigned long *flags)
> > > > >  {
> > > > >       struct sighand_struct *sighand;
> > > > > -
> > > > > +     /*
> > > > > +      * We are going to do rcu_read_unlock() under 
> > > > > spin_lock_irqsave().
> > > > > +      * Make sure we can not be preempted after rcu_read_lock(), see
> > > > > +      * rcu_read_unlock() comment header for details.
> > > > > +      */
> > > > > +     preempt_disable();
> > > >
> > > > The sad part is, this is going to break -rt.
> > >
> > > Hmm, why??
> >
> > Because in -rt, siglock is a mutex.
> 
> Yes, thanks... I thougt that -rt should handle this somehow, we have
> more examples of preempt_disable() + spin_lock().
> 
> OK, let's forger this patch. It was supposed to be a cleanup, it should
> not disturb -rt.
> 
> > > In fact this deadlock is not really possible in any case, scheduler locks
> > > should be fine under ->siglock (for example, signal_wake_up() is called
> > > under this lock).
> > >
> > > But, the comment above rcu_read_unlock() says:
> > >
> > >   Given that the set of locks acquired by rt_mutex_unlock() might change
> > >   at any time, a somewhat more future-proofed approach is to make sure
> > >   that that preemption never happens ...
> >
> > Hmm, I'm not sure we need to worry about this. As in -rt siglock is a
> > mutex, which is rt_mutex() itself, I highly doubt we will have
> > rt_mutex_unlock() grab siglock, otherwise that would cause havoc in -rt.
> 
> Yes. And, the changelog in a841796f "signal: align __lock_task_sighand() irq
> disabling and RCU" says:
> 
>       It is therefore possible that this RCU read-side critical
>       section will be preempted and later RCU priority boosted, which means
>       that rcu_read_unlock() will call rt_mutex_unlock() in order to deboost
>       itself, but with interrupts disabled. This results in lockdep splats
>       ...
>       It is quite possible that a better long-term fix is to make 
> rt_mutex_unlock()
>       disable irqs when acquiring the rt_mutex structure's ->wait_lock.
> 
> but this doesn't look right, raw_spin_lock(&lock->wait_lock) should be
> fine with irqs disabled or I am totally confused. rt_mutex_adjust_prio()
> does _irqsave/irqrestore, so this can't enable interrupts.
> 
> Paul, will you agree if we turn it into

If you guys continue the guarantee of no deadlock, I am OK with this change.

                                                        Thanx, Paul

> struct sighand_struct *__lock_task_sighand(struct task_struct *tsk,
>                                          unsigned long *flags)
> {
>       struct sighand_struct *sighand;
> 
>       rcu_read_lock();
>       for (;;) {
>               sighand = rcu_dereference(tsk->sighand);
>               if (unlikely(sighand == NULL))
>                       break;
> 
>               spin_lock_irqsave(&sighand->siglock, *flags);
>               if (likely(sighand == tsk->sighand))
>                       break;
>               spin_unlock_irqrestore(&sighand->siglock, *flags);
>       }
>       /*
>        * On the succesfull return we hold ->siglock. According to comment
>        * above rcu_read_unlock() this is against the rules, but scheduler
>        * locks are fine under this lock, signal_wake_up() takes them too.
>        */
>       rcu_read_unlock();
> 
>       return sighand;
> }
> 
> ?
> 
> Or I can leave this code alone, this is the minor cleanup. Just to me this
> sequence
> 
>       local_irq_save();
>       rcu_read_lock();
>       spin_lock();
> 
> looks a bit confusing/annoying even with the comment.
> 
> Oleg.
> 

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