On Thu, Oct 15, 2015 at 09:22:26AM +0800, Boqun Feng wrote:
> On Thu, Oct 15, 2015 at 08:53:21AM +0800, Boqun Feng wrote:
> > On Wed, Oct 14, 2015 at 02:44:53PM -0700, Paul E. McKenney wrote:
> > > On Wed, Oct 14, 2015 at 11:04:19PM +0200, Peter Zijlstra wrote:
> > > > On Wed, Oct 14, 2015 at 01:19:17PM -0700, Paul E. McKenney wrote:
> > > > > Suppose we have something like the following, where "a" and "x" are 
> > > > > both
> > > > > initially zero:
> > > > > 
> > > > >       CPU 0                           CPU 1
> > > > >       -----                           -----
> > > > > 
> > > > >       WRITE_ONCE(x, 1);               WRITE_ONCE(a, 2);
> > > > >       r3 = xchg(&a, 1);               smp_mb();
> > > > >                                       r3 = READ_ONCE(x);
> > > > > 
> > > > > If xchg() is fully ordered, we should never observe both CPUs'
> > > > > r3 values being zero, correct?
> > > > > 
> > > > > And wouldn't this be represented by the following litmus test?
> > > > > 
> > > > >       PPC SB+lwsync-RMW2-lwsync+st-sync-leading
> > > > >       ""
> > > > >       {
> > > > >       0:r1=1; 0:r2=x; 0:r3=3; 0:r10=0 ; 0:r11=0; 0:r12=a;
> > > > >       1:r1=2; 1:r2=x; 1:r3=3; 1:r10=0 ; 1:r11=0; 1:r12=a;
> > > > >       }
> > > > >        P0                 | P1                 ;
> > > > >        stw r1,0(r2)       | stw r1,0(r12)      ;
> > > > >        lwsync             | sync               ;
> > > > >        lwarx  r11,r10,r12 | lwz r3,0(r2)       ;
> > > > >        stwcx. r1,r10,r12  | ;
> > > > >        bne Fail0          | ;
> > > > >        mr r3,r11          | ;
> > > > >        Fail0:             | ;
> > > > >       exists
> > > > >       (0:r3=0 /\ a=2 /\ 1:r3=0)
> > > > > 
> > > > > I left off P0's trailing sync because there is nothing for it to order
> > > > > against in this particular litmus test.  I tried adding it and 
> > > > > verified
> > > > > that it has no effect.
> > > > > 
> > > > > Am I missing something here?  If not, it seems to me that you need
> > > > > the leading lwsync to instead be a sync.
> > 
> > I'm afraid more than that, the above litmus also shows that
> 
> I mean there will be more things we need to fix, perhaps even smp_wmb()
> need to be sync then..

That should not be necessary.  For smp_wmb(), lwsync should be just fine.

                                                                Thanx, Paul

> Regards,
> Boqun
> 
> >     CPU 0                           CPU 1
> >     -----                           -----
> > 
> >     WRITE_ONCE(x, 1);               WRITE_ONCE(a, 2);
> >     r3 = xchg_release(&a, 1);       smp_mb();
> >                                     r3 = READ_ONCE(x);
> > 
> >     (0:r3 == 0 && 1:r3 == 0 && a == 2) is not prohibitted
> > 
> > in the implementation of this patchset, which should be disallowed by
> > the semantics of RELEASE, right?
> > 
> > And even:
> > 
> >     CPU 0                           CPU 1
> >     -----                           -----
> > 
> >     WRITE_ONCE(x, 1);               WRITE_ONCE(a, 2);
> >     smp_store_release(&a, 1);       smp_mb();
> >                                     r3 = READ_ONCE(x);
> > 
> >     (1:r3 == 0 && a == 2) is not prohibitted
> > 
> > shows by:
> > 
> >     PPC weird-lwsync
> >     ""
> >     {
> >     0:r1=1; 0:r2=x; 0:r3=3; 0:r12=a;
> >     1:r1=2; 1:r2=x; 1:r3=3; 1:r12=a;
> >     }
> >      P0                 | P1                 ;
> >      stw r1,0(r2)       | stw r1,0(r12)      ;
> >      lwsync             | sync               ;
> >      stw  r1,0(r12)     | lwz r3,0(r2)       ;
> >     exists
> >     (a=2 /\ 1:r3=0)
> > 
> > 
> > Please find something I'm (or the tool is) missing, maybe we can't use
> > (a == 2) as a indication that STORE on CPU 1 happens after STORE on CPU
> > 0?
> > 
> > And there is really something I find strange, see below.
> > 
> > > > 
> > > > So the scenario that would fail would be this one, right?
> > > > 
> > > > a = x = 0
> > > > 
> > > >         CPU0                            CPU1
> > > > 
> > > >         r3 = load_locked (&a);
> > > >                                         a = 2;
> > > >                                         sync();
> > > >                                         r3 = x;
> > > >         x = 1;
> > > >         lwsync();
> > > >         if (!store_cond(&a, 1))
> > > >                 goto again
> > > > 
> > > > 
> > > > Where we hoist the load way up because lwsync allows this.
> > > 
> > > That scenario would end up with a==1 rather than a==2.
> > > 
> > > > I always thought this would fail because CPU1's store to @a would fail
> > > > the store_cond() on CPU0 and we'd do the 'again' thing, re-issuing the
> > > > load and now seeing the new value (2).
> > > 
> > > The stwcx. failure was one thing that prevented a number of other
> > > misordering cases.  The problem is that we have to let go of the notion
> > > of an implicit global clock.
> > > 
> > > To that end, the herd tool can make a diagram of what it thought
> > > happened, and I have attached it.  I used this diagram to try and force
> > > this scenario at https://www.cl.cam.ac.uk/~pes20/ppcmem/index.html#PPC,
> > > and succeeded.  Here is the sequence of events:
> > > 
> > > o Commit P0's write.  The model offers to propagate this write
> > >   to the coherence point and to P1, but don't do so yet.
> > > 
> > > o Commit P1's write.  Similar offers, but don't take them up yet.
> > > 
> > > o Commit P0's lwsync.
> > > 
> > > o Execute P0's lwarx, which reads a=0.  Then commit it.
> > > 
> > > o Commit P0's stwcx. as successful.  This stores a=1.
> > > 
> > > o Commit P0's branch (not taken).
> > > 
> > 
> > So at this point, P0's write to 'a' has propagated to P1, right? But
> > P0's write to 'x' hasn't, even there is a lwsync between them, right?
> > Doesn't the lwsync prevent this from happening?
> > 
> > If at this point P0's write to 'a' hasn't propagated then when?
> > 
> > Regards,
> > Boqun
> > 
> > > o Commit P0's final register-to-register move.
> > > 
> > > o Commit P1's sync instruction.
> > > 
> > > o There is now nothing that can happen in either processor.
> > >   P0 is done, and P1 is waiting for its sync.  Therefore,
> > >   propagate P1's a=2 write to the coherence point and to
> > >   the other thread.
> > > 
> > > o There is still nothing that can happen in either processor.
> > >   So pick the barrier propagate, then the acknowledge sync.
> > > 
> > > o P1 can now execute its read from x.  Because P0's write to
> > >   x is still waiting to propagate to P1, this still reads
> > >   x=0.  Execute and commit, and we now have both r3 registers
> > >   equal to zero and the final value a=2.
> > > 
> > > o Clean up by propagating the write to x everywhere, and
> > >   propagating the lwsync.
> > > 
> > > And the "exists" clause really does trigger: 0:r3=0; 1:r3=0; [a]=2;
> > > 
> > > I am still not 100% confident of my litmus test.  It is quite possible
> > > that I lost something in translation, but that is looking less likely.
> > > 
> > > > > Of course, if I am not missing something, then this applies also to 
> > > > > the
> > > > > value-returning RMW atomic operations that you pulled this pattern 
> > > > > from.
> > > > > If so, it would seem that I didn't think through all the possibilities
> > > > > back when PPC_ATOMIC_EXIT_BARRIER moved to sync...  In fact, I believe
> > > > > that I worried about the RMW atomic operation acting as a barrier,
> > > > > but not as the load/store itself.  :-/
> > > > 
> > > > AARGH64 does something very similar; it does something like:
> > > > 
> > > >         ll
> > > >         ...
> > > >         sc-release
> > > > 
> > > >         mb
> > > > 
> > > > Which I assumed worked for the same reason, any change to the variable
> > > > would fail the sc, and we go for round 2, now observing the new value.
> > > 
> > > I have to defer to Will on this one.  You are right that ARM and PowerPC
> > > do have similar memory models, but there are some differences.
> > > 
> > >                                                   Thanx, Paul
> > 
> > 


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