Hi Abylay,

Em Fri, 22 Jul 2016 13:54:37 -0400
Abylay Ospan <aos...@netup.ru> escreveu:

> some frontends (mentioned on lgdt3306a) wait timeout inside code like:
> for (i = 20; i > 0; i--) {
>   msleep(50);
> 
> If there is no-LOCK then dvbv5-scan spent a lot of time (doing 40x calls).
> This patch introduce timeout which 4 sec * multiply. So we do not wait more
> than 4 sec (or so) if no-LOCK.
> 
> Signed-off-by: Abylay Ospan <aos...@netup.ru>
> ---
>  utils/dvb/dvbv5-scan.c | 15 +++++++++++++++
>  1 file changed, 15 insertions(+)
> 
> diff --git a/utils/dvb/dvbv5-scan.c b/utils/dvb/dvbv5-scan.c
> index 689bc0b..1fc33d7 100644
> --- a/utils/dvb/dvbv5-scan.c
> +++ b/utils/dvb/dvbv5-scan.c
> @@ -182,12 +182,23 @@ static int print_frontend_stats(struct arguments *args,
>       return 0;
>  }
>  
> +/* return timestamp in msec */
> +uint64_t get_timestamp()
> +{
> +     struct timeval now;
> +     gettimeofday(&now, 0);
> +     return now.tv_sec * 1000 + now.tv_usec/1000;

This is not good, as gettimeofday() is not monotonic, and may be affected
by clock adjustments.

IMHO, the best would be to adjust the do_timeout() to handle
args->timeout_multiply.

Regards,
Mauro

> +}
> +
>  static int check_frontend(void *__args,
>                         struct dvb_v5_fe_parms *parms)
>  {
>       struct arguments *args = __args;
>       int rc, i;
>       fe_status_t status;
> +     uint64_t start = get_timestamp();
> +     /* msec timeout by default 4 sec * multiply */ 
> +     uint64_t timeout = args->timeout_multiply * 4 * 1000;
>  
>       args->n_status_lines = 0;
>       for (i = 0; i < args->timeout_multiply * 40; i++) {
> @@ -203,6 +214,10 @@ static int check_frontend(void *__args,
>               print_frontend_stats(args, parms);
>               if (status & FE_HAS_LOCK)
>                       break;
> +
> +             if ((get_timestamp() - start) > timeout)
> +                     break;
> +
>               usleep(100000);

It would also make sense to remove the usleep here and
use something else that would be checking timeout_flag,
like:

        for (i = 1; i < 100; i++) {
                if (timeout_flag)
                        break;
                usleep(1000);
        }


-- 
Thanks,
Mauro
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