Em Fri, 13 Apr 2018 11:15:16 +0200
Mason <slash....@free.fr> escreveu:

> On 12/04/2018 17:24, Mauro Carvalho Chehab wrote:
> 
> > As warned by smatch:
> >     drivers/media/rc/st_rc.c:110 st_rc_rx_interrupt() warn: this loop 
> > depends on readl() succeeding
> > 
> > If something goes wrong at readl(), the logic will stay there
> > inside an IRQ code forever. This is not the nicest thing to
> > do :-)
> > 
> > So, add a timeout there, preventing staying inside the IRQ
> > for more than 10ms.
> > 
> > Signed-off-by: Mauro Carvalho Chehab <mche...@s-opensource.com>
> > ---
> >  drivers/media/rc/st_rc.c | 16 ++++++++++------
> >  1 file changed, 10 insertions(+), 6 deletions(-)
> > 
> > diff --git a/drivers/media/rc/st_rc.c b/drivers/media/rc/st_rc.c
> > index d2efd7b2c3bc..c855b177103c 100644
> > --- a/drivers/media/rc/st_rc.c
> > +++ b/drivers/media/rc/st_rc.c
> > @@ -96,19 +96,24 @@ static void st_rc_send_lirc_timeout(struct rc_dev *rdev)
> >  
> >  static irqreturn_t st_rc_rx_interrupt(int irq, void *data)
> >  {
> > +   unsigned long timeout;
> >     unsigned int symbol, mark = 0;
> >     struct st_rc_device *dev = data;
> >     int last_symbol = 0;
> > -   u32 status;
> > +   u32 status, int_status;
> >     DEFINE_IR_RAW_EVENT(ev);
> >  
> >     if (dev->irq_wake)
> >             pm_wakeup_event(dev->dev, 0);
> >  
> > -   status  = readl(dev->rx_base + IRB_RX_STATUS);
> > +   /* FIXME: is 10ms good enough ? */
> > +   timeout = jiffies +  msecs_to_jiffies(10);
> > +   do {
> > +           status  = readl(dev->rx_base + IRB_RX_STATUS);
> > +           if (!(status & (IRB_FIFO_NOT_EMPTY | IRB_OVERFLOW)))
> > +                   break;
> >  
> > -   while (status & (IRB_FIFO_NOT_EMPTY | IRB_OVERFLOW)) {
> > -           u32 int_status = readl(dev->rx_base + IRB_RX_INT_STATUS);
> > +           int_status = readl(dev->rx_base + IRB_RX_INT_STATUS);
> >             if (unlikely(int_status & IRB_RX_OVERRUN_INT)) {
> >                     /* discard the entire collection in case of errors!  */
> >                     ir_raw_event_reset(dev->rdev);
> > @@ -148,8 +153,7 @@ static irqreturn_t st_rc_rx_interrupt(int irq, void 
> > *data)
> >  
> >             }
> >             last_symbol = 0;
> > -           status  = readl(dev->rx_base + IRB_RX_STATUS);
> > -   }
> > +   } while (time_is_after_jiffies(timeout));
> >  
> >     writel(IRB_RX_INTS, dev->rx_base + IRB_RX_INT_CLEAR);
> >    
> 
> Isn't this a place where the iopoll.h helpers might be useful?
> 
> e.g. readl_poll_timeout()
> 
> https://elixir.bootlin.com/linux/latest/source/include/linux/iopoll.h#L114

That won't work. Internally[1], readx_poll_timeout() calls
usleep_range().

[1] https://elixir.bootlin.com/linux/latest/source/include/linux/iopoll.h#L43

It can't be called here, as this loop happens at the irq
handler.

Thanks,
Mauro

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