Now, just to distract the honorable gurus from holding their mailboxes empty,
a bash programming contest. The winner gets life-time membership in 1unix.org!
The Problem:
Find the shortest, most intuitive, and most elegant way to extract the LAST parameter
passed to a bash shell script. An example when it may be necessary is
gcc -c -I/home/include -I/usr/local/include file.ads
-- you don't know the number of the parameters but need only the last one.
My solution:
-----last begin:
for last do a=0 # a=0 means "do nothing!"
done
echo $last
-----last end.
This is almost fine, except I'd rather refer to it as in history, directly, !$,
and I also hate the a=0 dummy statement -- is there an explicit null statement in bash,
such as ; by itself in C? However, a=0 is good since it doesn't invoke any programs.
I dare y'all for a better solution! :-)
(I tried to use $# for direct indexing, like ${$#}, but it fails.)
--
Cheers,
Alexy Khrabrov -- www.suffix.com -- Segmentation f%^(&
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