At 02:42 PM 12/4/02 -0500, Paul Kraus wrote:
Not in Perl. These two operations do different things, and neither does what I suspect you think they both do (increment Paul by 1). Example below:Odd we looked at the same problem and came up with completely opposing conclusions. My attempt to combine them was for the sake of readability. I know Perl has a 1000 ways to write the same statement. I thought there would be a better more readable way. Sort of like Paul = + 1 can be written Paul += Paul. The second of which is easier for me to look at.
#!/usr/bin/perl
$paul = 23 ;
#!/usr/bin/perl
$paul = 23 ;
$paul = +1 ;
$paul2 = 23 ;
$paul2 += $paul2 ;
print "paul=$paul but paul2 =$paul2\n" ;
#EOP
ray@waverly:~$ ./testme2.pl
paul=1 but paul2 =46
This offers a nice illustration of why I dislike most "shortcut" syntax. I even usually prefer to write $paul = $paul + 1 rather than its equivalent $paul++, except in highly conventionalized uses like "for" statements. YMMV, of course.
BTW, Alan's suggestion won't work either (either exactly as proposed or in the easy variants I could try ... though Perl is wonky enough that *some* variation on his idea might work). Two reasons:
1. $5 is a read-only variable so you can't apply the =~s operator to it.
2. In general, $a = $b = $c assigns to $a the return code from the operation $b = $c -- either 1 for success or 0 for failure -- not the value in $c.
Another nice example of why I hate "shortcut" syntax. Boring is better.
--
-------------------------------------------"Never tell me the odds!"--------
Ray Olszewski -- Han Solo
Palo Alto, California, USA [EMAIL PROTECTED]
-------------------------------------------------------------------------------
-
To unsubscribe from this list: send the line "unsubscribe linux-newbie" in
the body of a message to [EMAIL PROTECTED]
More majordomo info at http://vger.kernel.org/majordomo-info.html
Please read the FAQ at http://www.linux-learn.org/faqs
