Hi Lawson!
On Sat, 04 Jan 2003, [EMAIL PROTECTED] wrote:
> This also seems to work:
>
> find -name 'Makefile'|xargs -i perl -pi -e 's/-Werror//g' {}
First off thank you very much! It worked fine.
But now I still want to understand it ;)
What I dont understand is the:
1) "-i perl" option
man page says:
--replace[=replace-str], -i[replace-str]
Replace occurences of replace-str in the initial
arguments with names read from standard input.
Also, unquoted blanks do not terminate arguments.
If replace-str is omitted, it defaults to "{}"
(like for `find -exec'). Implies -x and -l 1.
As I understand this it calls perl and executes the regexp on a file.
The explanation of the -i option in man page of xargs and that it
calls perl doesnt fit together in my understanding.
2) "-pi" option
"-p" runs the "program" first through the C preprocessor, right? But
what for?
"-i" means that the file is edited in-place? What does that mean?
3) What is the {} for?
Thank you very much,
Axel
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