I've been looking at a couple of different sources of information, but hey -
if I post here I may get a specific answer rather than a general one.
I'm purchasing an 8Gb hard drive. I intend to put windows '98 on it (for
games) and linux on my existing 2Gb drive, which will become HD 2 (because
windows insists on beeing booted from HD1).
Apparently twice your memory is good for swap space, and the largest swap
you can use is 128M. Since I will have 128M of memory, I'd be looking at two
swap partitions of 128M - one on each drive.
So: I'm looking at
Hda - 8GB. hda1 Windows98 remainder, hda2 linux swap 128M.
Hdb 2 Gb. hdb1 Linux root, hdb2 linux swap 128M.
Since linux understands windows FAT32, I'll be able to mount my windows
C:\LinuxHome directory on linux /home - I hope.
However, I understand that it's a good idea to have two copies of the linux
system so that you can upgrade the kernel. If your new kernel dies, you boot
from the other one. The installation stuff I have does not seem to address
this. Does this mean 2 boot partitions on hdb? Is that possible?
Given that I want to get used to using linux for email and office, and want
to be able to upgrade to kernel 2.4 (which is coming out soonish I think),
how do you think I should set up my partitions?
TIA
