On 25-Sep-1999, Aldrin Aviananda wrote:
> gimana kalo:
> % perl -e '$a = 0; printf("%f\n",$a * -1 + 0)'
> 0.000000
> perl stores numbers as signed integer if possible...
hmm.. ok, udah mulai agak jelas skrg.. thanks.
tapi gimana roundingnya yah? masalah saya sebetulnya kurang lebih
begini:
[~]$ perl -e '$a=0.00000000000000000003; $a*=-1; printf("%#-7.3f\n",$a+0)'
-0.000
itu $a pokoknya kecil banget deh nilainya.. mendekati nol, but not
exactly.
--
Ronny Haryanto <[EMAIL PROTECTED]>
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