On Thu, May 04, 2006 at 09:18:57PM -0400, Bill Davidsen wrote:
> Erik Mouw wrote:
> >No, the other way around: RAID1 is a special case of RAID5.
> >
> No it isn't. If you have N drives in RAID1 you have N independent copies 
> of the data and no parity, there's just no corresponding thing in RAID5, 
> which has one copy of the data, plus parity. There is no special case, 
> it just doesn't work that way. Set N>2 and report back.

Just write out the formulas and it becomes obvious.

> Sorry, I couldn't find a diplomatic way to say you're completely wrong.

I guess we have to agree to disagree.


Erik

-- 
+-- Erik Mouw -- www.harddisk-recovery.com -- +31 70 370 12 90 --
| Lab address: Delftechpark 26, 2628 XH, Delft, The Netherlands
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