On 8/30/07, saeed bishara <[EMAIL PROTECTED]> wrote:
> you are right, I've another question regarding the function
> dma_wait_for_async_tx from async_tx.c, here is the body of the code:
> /* poll through the dependency chain, return when tx is complete */
> 1. do {
> 2. iter = tx;
> 3. while (iter->cookie == -EBUSY)
> 4. iter = iter->parent;
> 5.
> 6. status = dma_sync_wait(iter->chan, iter->cookie);
> 7. } while (status == DMA_IN_PROGRESS || (iter != tx));
>
> assume that:
> - The interrupt capability is not provided.
> - Request A was sent to chan 0
> - Request B that depends on A is sent to chan 1
> - Request C that depends on B is send to chan 2.
> - Also, assume that when C is handled by async_tx_submit(), B is still
> not queued to the dmaengine (cookie equals to -EBUSY).
>
> In this case, dma_wait_for_async_tx will be called for C, now, it
> looks for me that the do while will loop forever, even when A gets
> completed. this is because the iter will point to B after line 4, thus
> the iter != tx (C) will always become true.
>
You are right. There are no drivers in the tree that can hit this,
but it needs to be fixed up.
I'll submit the following change:
diff --git a/crypto/async_tx/async_tx.c b/crypto/async_tx/async_tx.c
index 0350071..bc18cbb 100644
--- a/crypto/async_tx/async_tx.c
+++ b/crypto/async_tx/async_tx.c
@@ -80,6 +80,7 @@ dma_wait_for_async_tx(struct dma_async_tx_descriptor *tx)
{
enum dma_status status;
struct dma_async_tx_descriptor *iter;
+ struct dma_async_tx_descriptor *parent;
if (!tx)
return DMA_SUCCESS;
@@ -87,8 +88,15 @@ dma_wait_for_async_tx(struct dma_async_tx_descriptor *tx)
/* poll through the dependency chain, return when tx is complete */
do {
iter = tx;
- while (iter->cookie == -EBUSY)
- iter = iter->parent;
+
+ /* find the root of the unsubmitted dependency chain */
+ while (iter->cookie == -EBUSY) {
+ parent = iter->parent;
+ if (parent && parent->cookie == -EBUSY)
+ iter = iter->parent;
+ else
+ break;
+ }
> saeed
Regards,
Dan
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