* Steven Scholz <[EMAIL PROTECTED]> wrote:
> with Linux 2.6.17-rt3 /proc/interrupts looks as described on
>
> http://rt.wiki.kernel.org/index.php/RT_PREEMPT_HOWTO
>
> CPU0
> 0: 11188 XT-PIC [........N/ 0]-level pit
> 1: 8 XT-PIC [........./ 0]-level i8042
> 2: 0 XT-PIC [........N/ 0]-level cascade
> 4: 131 XT-PIC [........./ 10]-level serial
> 11: 10 XT-PIC [........./ 0]-level eth0
> 14: 4087 XT-PIC [........./ 0]-level ide0
>
> But when using a Linux 2.6.19.1-rt15 it looks like
>
> CPU0
> 0: 15499 IO-APIC-edge timer
> 1: 8 IO-APIC-edge i8042
> 4: 161 IO-APIC-edge serial
> 9: 0 IO-APIC-fasteoi acpi
> 12: 3 IO-APIC-edge i8042
> 14: 4082 IO-APIC-edge ide0
> 16: 93 IO-APIC-fasteoi eth0
>
> which is pretty much the same as a vanilla 2.6.19.
>
> What does it mean? Is RT PREEMPT not working correctly?
i restored it to be as compatible with upstream as possible. You have a
PREEMPT_RT kernel if you have this message in the dmesg:
Real-Time Preemption Support (C) 2004-2006 Ingo Molnar
Ingo
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