On 25/04/2018 17:48:14+0200, Christoph Hellwig wrote:
> And stop trying to get a reference on the submodule, procfs code deals
> with release after and unloaded module and thus removed proc entry.
small typo here        ^

> 
> Signed-off-by: Christoph Hellwig <h...@lst.de>

Acked-by: Alexandre Belloni <alexandre.bell...@bootlin.com>


> ---
>  drivers/rtc/rtc-proc.c | 33 ++-------------------------------
>  1 file changed, 2 insertions(+), 31 deletions(-)
> 
> diff --git a/drivers/rtc/rtc-proc.c b/drivers/rtc/rtc-proc.c
> index 31e7e23cc5be..a9dd9218fae2 100644
> --- a/drivers/rtc/rtc-proc.c
> +++ b/drivers/rtc/rtc-proc.c
> @@ -107,40 +107,11 @@ static int rtc_proc_show(struct seq_file *seq, void 
> *offset)
>       return 0;
>  }
>  
> -static int rtc_proc_open(struct inode *inode, struct file *file)
> -{
> -     int ret;
> -     struct rtc_device *rtc = PDE_DATA(inode);
> -
> -     if (!try_module_get(rtc->owner))
> -             return -ENODEV;
> -
> -     ret = single_open(file, rtc_proc_show, rtc);
> -     if (ret)
> -             module_put(rtc->owner);
> -     return ret;
> -}
> -
> -static int rtc_proc_release(struct inode *inode, struct file *file)
> -{
> -     int res = single_release(inode, file);
> -     struct rtc_device *rtc = PDE_DATA(inode);
> -
> -     module_put(rtc->owner);
> -     return res;
> -}
> -
> -static const struct file_operations rtc_proc_fops = {
> -     .open           = rtc_proc_open,
> -     .read           = seq_read,
> -     .llseek         = seq_lseek,
> -     .release        = rtc_proc_release,
> -};
> -
>  void rtc_proc_add_device(struct rtc_device *rtc)
>  {
>       if (is_rtc_hctosys(rtc))
> -             proc_create_data("driver/rtc", 0, NULL, &rtc_proc_fops, rtc);
> +             proc_create_single_data("driver/rtc", 0, NULL, rtc_proc_show,
> +                             rtc);
>  }
>  
>  void rtc_proc_del_device(struct rtc_device *rtc)
> -- 
> 2.17.0
> 

-- 
Alexandre Belloni, Bootlin (formerly Free Electrons)
Embedded Linux and Kernel engineering
https://bootlin.com

Reply via email to