Why do we generate a warning when we compare two pointers
declared as safe? I understand why we do that when such beast gets
used as condition (i.e. implicitly compare with NULL), but what's
wrong with
int foo(void __safe *p, void __safe *q)
{
return p == q;
}
What did you want that check in evaluate_compare() to catch? Is that
about warning on explicit comparison with NULL?
Al, crawling through evaluate.c and fixing odd cases in typechecking...
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