On Fri, Jul 06, 2007 at 07:28:03PM -0700, Josh Triplett wrote: > > int foo(struct bar *p) __acquires(p); > > int bar(struct bar *p) __acquires(p); > > since you will have different symbols (same name, different scopes) here. > > Not necessarily. You need to substitute the actual arguments for the > formal arguments when you look at the context expression. Given > sufficiently good analysis, you could figure this case out; in > (n ? foo : bar)(p), both cases want to acquire &p->lock, or p in the > latter case.
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