Thanks Alan,
I am very thankful for your patient responses.

Regards,
Mukund Jampala


>-----Original Message-----
>From: Alan Stern [mailto:[EMAIL PROTECTED]
>Sent: Wednesday, March 01, 2006 8:45 PM
>To: Mukund JB.
>Cc: [EMAIL PROTECTED]; Randy.Dunlap
>Subject: RE: [linux-usb-devel] RE: Analyze the USB Control transfer
limits
>Table please..
>
>On Wed, 1 Mar 2006, Mukund JB. wrote:
>
>> >In other words, since low-speed USB runs at 1.5 Mb/s, that's 1500000
>> bits
>> >per second, or 1500 bits per frame, or 187.5 bytes per frame.  Since
>> you
>> >can't transfer half a byte, the number is rounded down to 187.
>>
>> I agree for low speed devices, the max allowable bandwidth for all
low
>> speed device put together is 1.5Mb/s.
>>
>> Please see last row of the table below:
>>
>> 8    24000   30%     3       19      24      --> last but one row
>>
>> As you said, for 8 bytes payload the max transfer possible are 3 and
so
>> maximum bytes/Frame are (3*8) = 24 bytes.
>> In a similar way what are the values "payload" and "max transfers" to
>> get the bytes/Frame as 187.
>>
>> Max  187500  187                     --> last row
>>
>> Hope I am clear.
>
>There are no "payload" and "max transfers" values for the last line.
>That's why it's formatted differently from the rest of the table.  The
>last line does not refer to control transfers; instead it talks about
the
>theoretical maximum capacity of the bus.
>
>If it helps you to understand the table better, pretend the last line
>isn't there at all.
>
>Alan Stern



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