Hi,

> > What if a hardware designer chooses to use GPIO '0' for one of these
> > functions?
> 
> It's explained earlier in the patch:
> 
Ok, it's obviously too early in the morning... :)

> ... that is, the GPIO_bit(x) in that gpio_set() call will
> morph (0|bits) into 0 so the test succeeds.
> 
Unless the chosen bit happens to be 'GPIO_IN', which is defined as 0.


Lothar Wassmann

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