On Tue, 20 Mar 2007, Oliver Neukum wrote: > Hi, > > from urb.c::usb_kill_urb(): > > if (!(urb && urb->dev && urb->dev->bus)) > return; > > Is this safe from a compiler point of view?
Of course it is. > Might a compiler actually evaluate the inner expression and then invert > the result? You mean, evaluate "(urb && urb->dev && urb->dev->bus)"? Yes indeed, it might. But in the course of evaluating that inner expression, the execution would stop as soon as it found that urb was NULL. That's guaranteed by the C language. Alan Stern ------------------------------------------------------------------------- Take Surveys. Earn Cash. Influence the Future of IT Join SourceForge.net's Techsay panel and you'll get the chance to share your opinions on IT & business topics through brief surveys-and earn cash http://www.techsay.com/default.php?page=join.php&p=sourceforge&CID=DEVDEV _______________________________________________ linux-usb-devel@lists.sourceforge.net To unsubscribe, use the last form field at: https://lists.sourceforge.net/lists/listinfo/linux-usb-devel
