On Mon, Jul 01, 2019 at 11:11:02PM +0800, Charles Yeh wrote:
> > > + if (spriv->quirks & PL2303_QUIRK_LEGACY) {
> > > + pl2303_update_reg(serial, 0, PL2303_FLOWCTRL_MASK,
> > > + 0x40);
> >
> > No need to break this line even if you end up with slightly more than 80
> > chars.
> >
> OK. I will ignore "WARNING: line over 80 characters".
Yeah, it's ok to go slightly above 80 chars when it improves readability.
> > > + } else if (spriv->type == &pl2303_type_data[TYPE_HXN]) {
> > > + pl2303_update_reg(serial, PL2303_HXN_FLOWCTRL,
> > > + PL2303_HXN_FLOWCTRL_MASK,
> > > + PL2303_HXN_CTRL_RTS_CTS);
> >
> > Again, continuation lines should be indented at least two tabs further
> > (you only use one tab now).
> >
>
> I have done it the way you do today...but after checking
> ./scripts/checkpatch.pl.. I got another warning message...
> So I am a little confused now...
> Previously before submitting.. must first pass ./scripts/checkpatch.pl
> check. No ERROR, or WARRING message...
>
> I will return to the office tomorrow ... I will post another warning
> message (according to the way you mentioned)
checkpatch isn't always right. Just remember to indent continuation
lines at least two tabs further, such as
pl2303_update_reg(serial, PL2303_HXN_FLOWCTRL,
PL2303_HXN_FLOWCTRL_MASK,
PL2303_HXN_CTRL_RTS_CTS);
> > } else if (spriv->type == &pl2303_type_data[TYPE_HXN]) {
> >
> > > + pl2303_vendor_write(serial,
> > > PL2303_HXN_RESET_CONTROL,
> > > + 0);
> >
> > You again completely ignored my question about why you're wring 0
> > instead of 3 here.
> >
> > I'll ignore your patch until you explain.
>
> 3. In pl2303_open: Because TYPE_HXN is different from the instruction of reset
> down/up stream used by TYPE_HX.
> Therefore, we will also execute different instructions here.
> The default of chip Reset Control is 0xFF(TYPE_HXN), therefore we will
> write 0x00 to reset down/up stream(TYPE_HXN).
I'm asking why you write the value 0 instead of 3 (or say, 0xfc)? Your
documentation said bit 0 and 1 are used to reset the up and downstream
pipes.
To be more specific; what happens if I
1. set bit 0
2. clear bit 0?
and leave the other bits alone (write back the same value, e.g. 0xfe).
Johan
